2794. Create Object from Two Arrays 🔒 

Description

Given two arrays keysArr and valuesArr, return a new object obj. Each key-value pair in obj should come from keysArr[i] and valuesArr[i].

If a duplicate key exists at a previous index, that key-value should be excluded. In other words, only the first key should be added to the object.

If the key is not a string, it should be converted into a string by calling String() on it.

Example 1:

Input: keysArr = ["a", "b", "c"], valuesArr = [1, 2, 3]
Output: {"a": 1, "b": 2, "c": 3}
Explanation: The keys "a", "b", and "c" are paired with the values 1, 2, and 3 respectively.

Example 2:

Input: keysArr = ["1", 1, false], valuesArr = [4, 5, 6]
Output: {"1": 4, "false": 6}
Explanation: First, all the elements in keysArr are converted into strings. We can see there are two occurrences of "1". The value associated with the first occurrence of "1" is used: 4.

Example 3:

Input: keysArr = [], valuesArr = []
Output: {}
Explanation: There are no keys so an empty object is returned.

Constraints:

keysArr and valuesArr are valid JSON arrays
2 <= JSON.stringify(keysArr).length, JSON.stringify(valuesArr).length <= 5 * 10⁵
keysArr.length === valuesArr.length

Solutions

Solution 1

TypeScript

function createObject(keysArr: any[], valuesArr: any[]): Record<string, any> {
    const ans: Record<string, any> = {};
    for (let i = 0; i < keysArr.length; ++i) {
        const k = String(keysArr[i]);
        if (ans[k] === undefined) {
            ans[k] = valuesArr[i];
        }
    }
    return ans;
}

JavaScript

/**
 * @param {Array} keysArr
 * @param {Array} valuesArr
 * @return {Object}
 */
var createObject = function (keysArr, valuesArr) {
    const ans = {};
    for (let i = 0; i < keysArr.length; ++i) {
        const k = keysArr[i] + '';
        if (ans[k] === undefined) {
            ans[k] = valuesArr[i];
        }
    }
    return ans;
};