2525. Categorize Box According to Criteria
Description
Given four integers length, width, height, and mass, representing the dimensions and mass of a box, respectively, return a string representing the category of the box.
- The box is
"Bulky"if:<ul> <li><strong>Any</strong> of the dimensions of the box is greater or equal to <code>10<sup>4</sup></code>.</li> <li>Or, the <strong>volume</strong> of the box is greater or equal to <code>10<sup>9</sup></code>.</li> </ul> </li> <li>If the mass of the box is greater or equal to <code>100</code>, it is <code>"Heavy".</code></li> <li>If the box is both <code>"Bulky"</code> and <code>"Heavy"</code>, then its category is <code>"Both"</code>.</li> <li>If the box is neither <code>"Bulky"</code> nor <code>"Heavy"</code>, then its category is <code>"Neither"</code>.</li> <li>If the box is <code>"Bulky"</code> but not <code>"Heavy"</code>, then its category is <code>"Bulky"</code>.</li> <li>If the box is <code>"Heavy"</code> but not <code>"Bulky"</code>, then its category is <code>"Heavy"</code>.</li>
Note that the volume of the box is the product of its length, width and height.
Example 1:
Input: length = 1000, width = 35, height = 700, mass = 300 Output: "Heavy" Explanation: None of the dimensions of the box is greater or equal to 104. Its volume = 24500000 <= 109. So it cannot be categorized as "Bulky". However mass >= 100, so the box is "Heavy". Since the box is not "Bulky" but "Heavy", we return "Heavy".
Example 2:
Input: length = 200, width = 50, height = 800, mass = 50 Output: "Neither" Explanation: None of the dimensions of the box is greater or equal to 104. Its volume = 8 * 106 <= 109. So it cannot be categorized as "Bulky". Its mass is also less than 100, so it cannot be categorized as "Heavy" either. Since its neither of the two above categories, we return "Neither".
Constraints:
1 <= length, width, height <= 1051 <= mass <= 103
Solutions
Solution 1: Simulation
We can simulate according to the problem description.
The time complexity is $O(1)$, and the space complexity is $O(1)$.
Python3
class Solution:
def categorizeBox(self, length: int, width: int, height: int, mass: int) -> str:
v = length * width * height
bulky = int(any(x >= 10000 for x in (length, width, height)) or v >= 10**9)
heavy = int(mass >= 100)
i = heavy << 1 | bulky
d = ['Neither', 'Bulky', 'Heavy', 'Both']
return d[i]
Java
class Solution {
public String categorizeBox(int length, int width, int height, int mass) {
long v = (long) length * width * height;
int bulky = length >= 10000 || width >= 10000 || height >= 10000 || v >= 1000000000 ? 1 : 0;
int heavy = mass >= 100 ? 1 : 0;
String[] d = {"Neither", "Bulky", "Heavy", "Both"};
int i = heavy << 1 | bulky;
return d[i];
}
}
C++
class Solution {
public:
string categorizeBox(int length, int width, int height, int mass) {
long v = (long) length * width * height;
int bulky = length >= 10000 || width >= 10000 || height >= 10000 || v >= 1000000000 ? 1 : 0;
int heavy = mass >= 100 ? 1 : 0;
string d[4] = {"Neither", "Bulky", "Heavy", "Both"};
int i = heavy << 1 | bulky;
return d[i];
}
};
Go
func categorizeBox(length int, width int, height int, mass int) string {
v := length * width * height
i := 0
if length >= 10000 || width >= 10000 || height >= 10000 || v >= 1000000000 {
i |= 1
}
if mass >= 100 {
i |= 2
}
d := [4]string{"Neither", "Bulky", "Heavy", "Both"}
return d[i]
}
TypeScript
function categorizeBox(length: number, width: number, height: number, mass: number): string {
const v = length * width * height;
let i = 0;
if (length >= 10000 || width >= 10000 || height >= 10000 || v >= 1000000000) {
i |= 1;
}
if (mass >= 100) {
i |= 2;
}
return ['Neither', 'Bulky', 'Heavy', 'Both'][i];
}
Rust
impl Solution {
pub fn categorize_box(length: i32, width: i32, height: i32, mass: i32) -> String {
let v = (length as i64) * (width as i64) * (height as i64);
let mut i = 0;
if length >= 10000 || width >= 10000 || height >= 10000 || v >= 1000000000 {
i |= 1;
}
if mass >= 100 {
i |= 2;
}
let d = vec!["Neither", "Bulky", "Heavy", "Both"];
d[i].to_string()
}
}
Solution 2
Python3
class Solution:
def categorizeBox(self, length: int, width: int, height: int, mass: int) -> str:
v = length * width * height
bulky = any(x >= 10000 for x in (length, width, height)) or v >= 10**9
heavy = mass >= 100
if bulky and heavy:
return "Both"
if bulky:
return "Bulky"
if heavy:
return "Heavy"
return "Neither"
Java
class Solution {
public String categorizeBox(int length, int width, int height, int mass) {
long v = (long) length * width * height;
boolean bulky = length >= 1e4 || width >= 1e4 || height >= 1e4 || v >= 1e9;
boolean heavy = mass >= 100;
if (bulky && heavy) {
return "Both";
}
if (bulky) {
return "Bulky";
}
if (heavy) {
return "Heavy";
}
return "Neither";
}
}
C++
class Solution {
public:
string categorizeBox(int length, int width, int height, int mass) {
long v = (long) length * width * height;
bool bulky = length >= 1e4 || width >= 1e4 || height >= 1e4 || v >= 1e9;
bool heavy = mass >= 100;
if (bulky && heavy) {
return "Both";
}
if (bulky) {
return "Bulky";
}
if (heavy) {
return "Heavy";
}
return "Neither";
}
};
Go
func categorizeBox(length int, width int, height int, mass int) string {
v := length * width * height
bulky := length >= 1e4 || width >= 1e4 || height >= 1e4 || v >= 1e9
heavy := mass >= 100
if bulky && heavy {
return "Both"
}
if bulky {
return "Bulky"
}
if heavy {
return "Heavy"
}
return "Neither"
}
TypeScript
function categorizeBox(length: number, width: number, height: number, mass: number): string {
const v = length * width * height;
const bulky = length >= 1e4 || width >= 1e4 || height >= 1e4 || v >= 1e9;
const heavy = mass >= 100;
if (bulky && heavy) {
return 'Both';
}
if (bulky) {
return 'Bulky';
}
if (heavy) {
return 'Heavy';
}
return 'Neither';
}
Rust
impl Solution {
pub fn categorize_box(length: i32, width: i32, height: i32, mass: i32) -> String {
let v = length * width * height;
let bulky = length >= 10000
|| width >= 10000
|| height >= 10000
|| (length as i64) * (width as i64) * (height as i64) >= 1000000000;
let heavy = mass >= 100;
if bulky && heavy {
return "Both".to_string();
}
if bulky {
return "Bulky".to_string();
}
if heavy {
return "Heavy".to_string();
}
"Neither".to_string()
}
}